1/18/2026 Created the blog. iℏ∂∂tΨ(r,t)=H^Ψ(r,t)i\hbar \frac{\partial}{\partial t} \Psi(\mathbf{r}, t) = \hat{H} \Psi(\mathbf{r}, t)iℏ∂t∂Ψ(r,t)=H^Ψ(r,t)